There are 96 apples and 112 oranges. These fruits are packed in boxes in such a way that each box contains fruits of the same variety, and every box contains an equal number of fruits. Find the minimum number of boxes in which all the fruits can be packed.

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Solution

For a number of boxes to be the least, the number of fruits in each box should be maximum.

As per the given data, the number of fruits in each box is equal to the $H C F$ of $96$ and $112$ , i.e., $16$ .

Therefore, minimum number of boxes = $\frac{96}{16} + \frac{112}{16} = 13$ .

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There are 96 apples and 112 oranges. These fruits are packed in boxes in such a way that each box contains fruits of the same variety, and every box contains an equal number of fruits. Find the minimum number of boxes in which all the fruits can be packed.

For a number of boxes to be the least, the number of fruits in each box should be maximum.As per the given data, the number of fruits in each box is equal to the HCF of 96 and 112, i.e., 16.Therefore, minimum number of boxes = 9616+11216=13.

For a number of boxes to be the least, the number of fruits in each box should be maximum.

As per the given data, the number of fruits in each box is equal to the $H C F$ of $96$ and $112$ , i.e., $16$ .

Therefore, minimum number of boxes = $\frac{96}{16} + \frac{112}{16} = 13$ .