Question

There are $9999$ tickets bearing numbers 0001, 0002,.....,9999. If one ticket is selected from these tickets at random, the probability that the numbers on the ticket will consists of all different digits is

• A. 5040/9999
• B. 5000/9999
• C. 5030/9999
• D. None of these

Answer 1

The correct option is A 5040/9999

Total number of ways in selecting a ticket from 9999 tickets = 9999 ways

Total number of ways in selecting a ticket in which all the four digits are different = $10\times 9\times 8\times 7=5040$ ways.

$\therefore$ Probability that numbers on the tickets will consists of all different digits = $\frac{5040}{9999}$