There are atomic (Caesium) clocks capable of measuring time with an accuracy of 1 part in 1011. If two such clocks are operated to precision, then after running for 5000 years, these will record a difference of :
A
1day
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B
1s
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C
1011s
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D
1year
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Solution
The correct option is B1s 5000yrs=5000×365×24×3600s = 1.5×1011s Since accuracy is 1 part in 1011 s, the difference will be of 1s.