Question

There are different $5$ green dyes, $4$ different blue dyes and $3$ different red dyes. Find the number of combinations of dyes that can be chosen.

• A. $2^{12}-1$
• B. $5^{12}-1$
• C. $3^{12}-1$
• D. None of these

Answer 1

The correct option is A $2^{12}-1$

$5$ different green dyes

$4$ different blue dyes

$3$ different red dyes

Total number of ways to choose $=$ $2^{12}$ which includes $1$ empty case

So ways are $2^{12}-1$