The correct option is D C
A > C -----(i), B > D -----(ii), E < B --------(iii), E > C ---------(iv), C > D ---------(v)
from (i) and (v), we get A > C > D ---------(I)
from (iii) and (iv), we get B > E > C --------(II)
From (I) and (II) , it is clear that 'D' is the thinnest.