There are five boys A,B,C,D,E. The order of their height is A < B < C < D < E. Number of ways in which they have to be arranged in 4 seats in increasing order of their height such that C & E are never adjacent, is

10

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6

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4

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8

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Solution

The correct option is C $4$
The possible arrangements are
ABCD
BCDE
ABDE
ACDE
4 possible arrangements

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There are five boys A,B,C,D,E. The order of their height is A < B < C < D < E. Number of ways in which they have to be arranged in 4 seats in increasing order of their height such that C & E are never adjacent, is

The correct option is C 4The possible arrangements areABCDBCDEABDEACDE4 possible arrangements

The correct option is C $4$
The possible arrangements are
ABCD
BCDE
ABDE
ACDE
4 possible arrangements