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Question

There are four arithmetic means between 2 and −18. The means are

A
4,7,10.13
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B
1,4,7,10
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C
2,5,9,13
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D
2,6,10,14
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Solution

The correct option is D 2,6,10,14
Let the mean be X1,X2,X3,X4 and the common difference be b; then 2,X1,X2,X3,X4,18 are in A.P.;
18=2+5b5b=20b=4
Hence, X1=2+b=2+(4)=2;X2=2+2b=28=6
X3=2+3b=212=10;X4=2+4b=216=14
The required means are 2,6,10,14.

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