1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# There are four children A, B, C and D. A has 6 chocolates, B has 7 chocolates, C has 8 chocolates and D has 10 chocolates. Which of these children have the average number of chocolates?

A

A

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B

B

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C

C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

D

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C C The average number of chocolates is 6+7+8+104 =314=7.75 Now the closest integral number to 7.75 is 8. Thus, we can say that the child with 8 chocolates has the average number of chocolates, which would be C. Note that the actual average is 7.75.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Mean - Ungrouped Data
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program