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Question

There are four children A, B, C and D. A has 6 chocolates, B has 7 chocolates, C has 8 chocolates and D has 10 chocolates. Which of these children have the average number of chocolates?


A

A

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B

B

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C

C

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D

D

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Solution

The correct option is C

C


The average number of chocolates is

6+7+8+104
=314=7.75

Now the closest integral number to 7.75 is 8. Thus, we can say that the child with 8 chocolates has the average number of chocolates, which would be C.

Note that the actual average is 7.75.


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