Question

There are four children A, B, C and D. A has 6 chocolates, B has 7 chocolates, C has 8 chocolates and D has 11 chocolates. Who has the average number of chocolates?

• A. A
• B. B
• C. C
• D. D

Answer 1

The correct option is C

C

The average number of chocolates is

$\frac{6+7+8+11}{4}$
$=\frac{32}{4}=8$

Now that the actual average is 8, we can say that the child with 8 chocolates has the average number of chocolates, which would be C.