Question

There are four children A,B,C and D. A has 6 chocolates, B has 7 chocolates, C has 8 chocolates and D has 11 chocolates. Which of these children has the average number of chocolates?

• A. A
• B. B
• C. C
• D. D

Answer 1

The correct option is C

C

The average number of chocolates is

$\frac{6+7+8+11}{4}$
$=\frac{32}{4}=8$

So, the child with 8 chocolates has the average number of chocolates. So, child C has the average number of chocolates.