Question 118

There are four containers that are arranged in the ascending order of their heights. If the of the smallest container given in figure is expressed as $\frac{7}{25} x = 10.5$ cm Then, find the height of the largest container.

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Solution

From the above figure, it is given that height of the smallest cylinder is 10.5 cm it is also given that, height of smallest cylinder in terms of x is $\frac{7}{25} x,$ where x is height of largest cylinder
Then , $\frac{7}{25} x = 10.5$
$\Rightarrow x = \frac{10.5}{1} \times \frac{25}{7} = \frac{10.5 \times 25}{7} = \frac{262.5}{7} = 37.5 c m$
Hence, height of the container is 37.5 cm

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Question 118 There are four containers that are arranged in the ascending order of their heights. If the of the smallest container given in figure is expressed as 725x=10.5 cm Then, find the height of the largest container.

From the above figure, it is given that height of the smallest cylinder is 10.5 cm it is also given that, height of smallest cylinder in terms of x is 725x, where x is height of largest cylinder Then , 725x=10.5 ⇒x=10.51×257=10.5×257=262.57=37.5cm Hence, height of the container is 37.5 cm

Question 118

There are four containers that are arranged in the ascending order of their heights. If the of the smallest container given in figure is expressed as $\frac{7}{25} x = 10.5$ cm Then, find the height of the largest container.