Question

There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

Answer 1

Here total members in the council
= 4 + 6 = 10
One member is selected out of 10 members
$\therefore$ $n\left(A\right){=}^6{C}_1=10$
Let A be the event that the member is a woman.
$\therefore n\left(A\right){=}^6{C}_1=6$

$\text{Thus}P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{6}{10}=\frac{3}{5}.$