There are four salts of the type MX - M X 2- M X 3 and M X 4 and all have the same value of K sp - 1-0 - 10-6- The salt that has maximum solubility-A- MXB- M X2C- M X3D- M X4

The correct option is B For MX: S = √(K_SP) = √(10^ 6) = 10^ 3 mol L^ 1 For MX_2 : S = √(K_SP/4) = √(10^ 6/4) = 6.29 × 10^ 3 mol L^ 1 For MX_3 : S = √(K_SP/ ...

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Standard XII

Chemistry

Solubility

There are fou...

Question

There are four salts of the type $M X$ , $M X_{2}$ , $M X_{3}$ and $M X_{4}$ and all have the same value of $K_{s p}$ : $1.0 \times 10^{- 6}$ . The salt that has maximum solubility.

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Solution

The correct option is B

For MX: $S$ = $\sqrt{K_{S P}}$ = $\sqrt{10^{- 6}}$ = $10^{- 3}$ $m o l L^{- 1}$

For $M X_{2}$ : $S$ = $\sqrt[3]{\frac{K_{S P}}{4}}$ = $\sqrt[3]{\frac{10^{- 6}}{4}}$ = $6.29 \times 10^{- 3}$ $m o l L^{- 1}$

For $M X_{3}$ : $S$ = $\sqrt[4]{\frac{K_{S P}}{27}}$ = $\sqrt[4]{\frac{10^{- 6}}{27}}$ = $1.38 \times 10^{- 2}$ $m o l L^{- 1}$

For $M X_{4}$ : $S$ = $\sqrt[5]{\frac{K_{S P}}{108}}$ = $\sqrt[5]{\frac{10^{- 6}}{108}}$ = $2.47 \times 10^{- 2} m o l L^{- 1}$

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There are four salts of the type MX, MX2, MX3 and MX4 and all have the same value of Ksp: 1.0 × 10−6. The salt that has maximum solubility.

The correct option is B For MX: S = √KSP = √10−6 = 10−3 molL−1 For MX2 : S = 3√KSP4 = 3√10−64 = 6.29 × 10−3 molL−1 For MX3 : S = 4√KSP27 = 4√10−627 = 1.38 × 10−2 molL−1 For MX4 : S = 5√KSP108 = 5√10−6108 = 2.47 × 10−2 molL−1

There are four salts of the type $M X$ , $M X_{2}$ , $M X_{3}$ and $M X_{4}$ and all have the same value of $K_{s p}$ : $1.0 \times 10^{- 6}$ . The salt that has maximum solubility.