Let the 4 numbers be a , b , c and d
Mean of the first 2 numbers, a and b = 4
So,a+b=4×2=8—(i)
Mean of the first 3 numbers, a, b and c = 9
So,a+b+c=9×3=27–(ii)
From equations (i) and (ii),
Third number, c = 27 -8 = 19
Mean of all the 4 numbers = 15
So,a+b+c+d=15×4=60–(iii)
From equations (ii) and (iii),
Fourth number,d = 60 - 27 = 33
Now, we got 2 unknown numbers; c = 19 and d = 33
It is given in the question that one of the numbers is 2.
So, let a = 2
Therefore, the third unknown number, b = 60 - (19 +33 +2)
⇒b=6
Hence, the three other numbers are 6, 19 and 33