wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

There are m persons sitting in a row. Two of them are selected at random. The probability that the two selected person are not together is

A
2/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
m(m1)(m+1)(m+2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 12m
The total number of ways of selecting two persons out of m is mC2=m(m1)2
The number of ways in which the two selected person are together is (m1).
Therefore, the number of ways in which the two selected persons are not together is mC2(m1)=(m1)(m2)2
Thus, the probability of the required event is (m1)(m2)/2m(m1)/2=m2m=12m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bayes Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon