There are many gas molecules $N H_{3}$ , $C O$ , $C H_{4}$ and $S O_{2}$ in a group once. They were discussing about who would be the better absorbed on charcoal. So they decided to have the race among themselves to prove it as to who would be absorbed more in the same time.
Who do you think won?

C O

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N H_{3}

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C H_{4}

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S O_{2}

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Solution

The correct option is B $N H_{3}$
Because, A gas with a critical temperature i.e a more easily liquefiable gas adsorbed to a greater extent.
$N H_{3}$ is having higher critical temperature and large van der waals forces of attraction.

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