Question

There are $n_1$ photons of frequency ${\gamma }_1$ in a beam of light. In an equally energetic beam, there are $n_2$ photons of frequency ${\gamma }_2$ . Then the correct relation is

• A. $\frac{n_1}{n_2}=1$
• B. $\frac{n_1}{n_2}=\frac{{\gamma }_1}{{\gamma }_2}$
• C. $\frac{n_1}{n_2}=\frac{{\gamma }_2}{{\gamma }_1}$
• D. $\frac{n_1}{n_2}=\frac{{\gamma }_1^2}{{\gamma }_2^2}$.

Answer 1

The correct option is C

$\frac{n_1}{n_2}=\frac{{\gamma }_2}{{\gamma }_1}$

$E=nhv\Rightarrow v\propto \frac{1}{n}\Rightarrow \frac{n_1}{n_2}=\frac{{\gamma }_2}{{\gamma }_1}$.