Question

There are $n$ different books and each book has $p$ copies. The number of selection of books from these is-

• A. $(p+1{)}^n-1$
• B. $(p+1{)}^n-2$
• C. $n(p+1)-1$
• D. None of these

Answer 1

The correct option is A $(p+1{)}^n-1$

We have $p$ copies of each of $n$ different books.

Number of ways to select from p copies: $p+1$

Total no. of ways:

$(p+1)(p+1)(p+1)................n$ times

${(p+1)}^n$

Number of different ways of selection is

${(p+1)}^n-1$