Question

There are $n$ different books and $p$ copies of each, find the number of ways in which a selection be made from them.

• A. $(p+1{)}^n-1$
• B. $(n+1{)}^p-1$
• C. $(p-1{)}^n-1$
• D. $(p+1{)}^n+1$

Answer 1

The correct option is A $(p+1{)}^n-1$

We have '$p$' copies of each of '$n$' different books.
Number of ways to select from $p$ copies:
$p+1$
Total no. of ways:
$(p+1)(p+1))p+1)................n$ times
$(p+1{)}^n$
Number of different ways of selection is
$(p+1{)}^n-1$