There are p,q, r points on three parallel lines L1 ,L2 and L3 all of which lie in one plane. Prove that the number of triangles which can be formed with vertices at their points is p+q+rC3−PC3−qC3−rC3
Open in App
Solution
Total number of points are p + q + r. Number of triangles is p+q+rC3. The points on L1 will not form a triangle. Hence exclude pC3 and similarly exclude qC3 and rC3 for q points on L2 and r points on L3.