Question

There are seven white and one brown egg in an egg box. Ruchira decides to make a two-egg omelette. She takes out each egg from the box without looking at its colour. What is the probability that Ruchira gets an omelette made from
(i) Two white eggs (ii) One white and one brown egg (iii) Two brown eggs

• A. (i) $\frac{3}{4}$ (ii)$\frac{1}{4}$ (iii) 0
• B. (i) $\frac{3}{8}$ (ii)$\frac{1}{4}$ (iii) 0
• C. (i) $\frac{3}{4}$ (ii)$\frac{1}{2}$ (iii) 0
• D. (i) $\frac{1}{4}$ (ii)$\frac{3}{4}$ (iii) 0

Answer 1

The correct option is A (i) $\frac{3}{4}$ (ii)$\frac{1}{4}$ (iii) 0

7 white eggs 1 brown eggs

She takes two eggs one by one without replacement

i)Probability of getting two white eggs=WW=(7/8)*(6/7)=3/4

i)Probability of getting one white and one brown egg=WB+BW

=(7/8)*(1/7)+(1/8)*(7/7)=1/4

III)since there are only one brown egg probability of getting two brown egg is zero