There are six plates of equal are $A$ and separation between the plates is $d (d << A)$ are arranged as shown in figure. The equivalent capacitance between points $2$ and $5,$ is $α \frac{ε_{0} A}{d} .$ Then find the value of $α .$

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Solution

$C_{n e t} = (\frac{C}{2} + \frac{C}{2})$
$C_{n e t} = C = ε_{0} \frac{A A}{d} = α ε_{0} \frac{A}{d}$
$α = 1$

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There are six plates of equal are A and separation between the plates is d(d<<A) are arranged as shown in figure. The equivalent capacitance between points 2 and 5, is αε0Ad. Then find the value of α.

Cnet=(C2+C2)Cnet=C=ε0AAd=αε0Adα=1

There are six plates of equal are $A$ and separation between the plates is $d (d << A)$ are arranged as shown in figure. The equivalent capacitance between points $2$ and $5,$ is $α \frac{ε_{0} A}{d} .$ Then find the value of $α .$

$C_{n e t} = (\frac{C}{2} + \frac{C}{2})$
$C_{n e t} = C = ε_{0} \frac{A A}{d} = α ε_{0} \frac{A}{d}$
$α = 1$