There are some deposits of nitrates and phosphates in earth's crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes with transition metal ions. Hybridisation easily explains the case of sigma donation capability of $N H_{3}$ and $P H_{3}$ . Phosphine is a flammable gas and is prepared from white phosphorus.

Which phosphorous on reaction with NaOH gives $P H_{3}$ as one of the product. This is a

dimerisation reaction

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disproportionation reaction

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condensation reaction

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precipitation reaction

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Solution

The correct option is B disproportionation reaction
White phosphorus undergo disproportionation in alkaline medium.
$P_{4} + N a O H \to P H_{3} + N a H_{2} P O_{2}$

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Similar questions

Q. There are some deposits of nitrates and phosphates in earth's crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes with transition metal ions. Hybridisation easily explains the case of sigma donation capability of

N H_{3}

and

P H_{3}

. Phosphine is a flammable gas and is prepared from white phosphorus.

Which phosphorous on reaction with NaOH gives

P H_{3}

as one of the product. This is a

N H_{3}

and

P H_{3}

. Phosphine is a flammable gas and is prepared from white phosphorus.

Among the following, the correct statement is

N H_{3}

and

P H_{3}

. Phosphine is a flammable gas and is prepared from white phosphorus.

Among the following, the correct statement is

Ammonia forms a large number of complexes with transition metal ions. Hybridisation easily explains the case of sigma donation capability of $N H_{3}$ and $P H_{3}$ .
Choose the correct statement from the following:

Q. The reaction of white phosphorous with aqueous

N a O H

gives phosphine along with another phosphorous containing compound. The reaction is a:

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The correct option is B disproportionation reactionWhite phosphorus undergo disproportionation in alkaline medium. P4+NaOH→PH3+NaH2PO2

The correct option is B disproportionation reaction
White phosphorus undergo disproportionation in alkaline medium.
$P_{4} + N a O H \to P H_{3} + N a H_{2} P O_{2}$