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Question

There are three consecutive numbers whose sum is 129. Find the square of the middle one.

A
1849
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B
1764
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C
1829
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D
1936
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Solution

The correct option is A 1849
Let numbers be x, x + 1, x + 2
According to question,
(x) + (x + 1) + (x + 2) = 129
(3x+3) = 129
3x = 129-3
3x = 126
x = 42
x+1 = 43
x2 = 43 × 43 = 1849.

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