CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

There are three piles of identical red, blue and green balls and each pile contains at least 10 balls. The number of ways of selecting 10 balls if twice as many red balls as green balls are to be selected, is
  1. 4
  2. 8
  3. 6
  4. 3


Solution

The correct option is A 4
Let the number of green balls be x. Let the number of red balls is 2x. Let the number of blue balls be y. Then, x+2x+y=103x+y=10y=103x

Clearly, x can take values 0,1,2,3. The corresponding values of y are 10,7,4 and 1. Thus the possibilities are (0,10,0),(2,7,1),(4,4,2) and (6,1,3), where (r,b,g) denotes the number of red, blue and green balls

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image