There are three pillars X, Y and Z of different heights. Three spiders A, B and C start to climb on these pillars simultaneously. In one chance A climbs on X 5 cm but slips down 1 cm. B climbs on Y 6 cm but slips down 3 cm. C climbs on Z 7 cm but slips down 2 cm. If each requires 50 chances to reach the top of the pillar, what is the height of the shortest pillar?

144 cm

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152 cm

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153 cm

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141 cm

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Solution

The correct option is A 153 cm
Distance covered by A in 50 chance=49(5-1)+5=201 Cm
Distance covered by B in 50 chance=49(6-3)+6=153 Cm
Distance covered by C in 50 chance=49(7-2)+7=252 Cm
Hence the height of the shortest pillar=153 m

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The correct option is A 153 cmDistance covered by A in 50 chance=49(5-1)+5=201 CmDistance covered by B in 50 chance=49(6-3)+6=153 CmDistance covered by C in 50 chance=49(7-2)+7=252 CmHence the height of the shortest pillar=153 m

The correct option is A 153 cm
Distance covered by A in 50 chance=49(5-1)+5=201 Cm
Distance covered by B in 50 chance=49(6-3)+6=153 Cm
Distance covered by C in 50 chance=49(7-2)+7=252 Cm
Hence the height of the shortest pillar=153 m