wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

There are three possible path from P to Q. A particle is moved through there three paths given. Initial speed in all three cases is same (path are frictionless ). Then which is/are correct about time taken tA,tB,tC in path A,B,C respectively.
760776_9adc314a82a24d0ea159f21f9e383773.png

A
tA>tB>tC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
tA=tB=tc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
tA<tB<tC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Data insufficient
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A tA>tB>tC
tA>tB>tC
SA=SB=SC
VA<VB<VC
V α acceleration α Force
Force in the direction of motion in A is opposite of motion ,then in B no force present and in C .Force in the direction of motion in C
VA<VB<VC.
tA>tB>tC

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Why Is the Center of Mass the Real Boss?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon