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Question

There are three sources of sound of equal intensity with frequencies 400, 401, 402 vibrations/sec. The number of beats heard per second is

A
1
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B
2
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C
3
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D
0
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Solution

The correct option is A 1
Resultant displacement of the wave by these three wave is
y=asin2π400t+asin2π401t+asin2π402t
y=a(1+2cos2πt)sin2π401t
So the resultant magnitude a(1+2cos2πt) has a maximum when,
cos2πt=1
or, t=0,1,2...
The time interval between two successive maximum is 1 sec.
So beat frequency is 1sec.

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