Question

There are three tankers whose capacities are in the ratio 4 : 5 : 6. If the largest water tanker can hold a capacity of 3600 liters, then find the capacity of the other two tankers in liters.

• A. 3600, 3000
• B. 2400,3000
• C. 3000, 2000
• D. 2000, 2400

Answer 1

The correct option is B

2400,3000

Let the capacity of the water tankers be 4$x$, 5$x$ and 6$x$ .

Given that the capacity of the largest tanker = 3600 Liters

Hence 6 $x$ = 3600 liters

$x$ = $\frac{3600}{6}$

= 600

$\therefore$ The capacity of the smallest tanker = $4\times \left(600\right)$= 2400 liters

The capacity of the other tanker = $5\times \left(600\right)$ = 3000 liters