There are three trees $T_{1}$ , $T_{2}$ and $T_{3}$ in a row. The ratio of height of $T_{1}$ to that of $T_{2}$ is same as the ratio of height of $T_{2}$ to that of $T_{3}$ . Given, the height of $T_{1}$ is $10$ m and the height of $T_{3}$ is $40$ m. What is the height of tree $T_{2}$ ?

15 m

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20 m

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25 m

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30 m

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Solution

The correct option is B 20 m
Let, the heights of $T_{1}$ , $T_{2}$ and $T_{3}$ be $t_{1}$ , $t_{2}$ and $t_{3}$ m respectively.

Given,
$\frac{t_{1}}{t_{2}} = \frac{t_{2}}{t_{3}} \frac{10}{t_{2}} = \frac{t_{2}}{40}$
Cross multiplying,
$\Rightarrow t_{2} \times t_{2} = 20 \times 20$
$\Rightarrow t_{2} = 20 m$

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There are three trees T1, T2 and T3 in a row. The ratio of height of T1 to that of T2 is same as the ratio of height of T2 to that of T3. Given, the height of T1 is 10 m and the height of T3 is 40 m. What is the height of tree T2?

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There are three trees $T_{1}$ , $T_{2}$ and $T_{3}$ in a row. The ratio of height of $T_{1}$ to that of $T_{2}$ is same as the ratio of height of $T_{2}$ to that of $T_{3}$ . Given, the height of $T_{1}$ is $10$ m and the height of $T_{3}$ is $40$ m. What is the height of tree $T_{2}$ ?