wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

There are three tuning forks A, B and C. Frequency of A is 250 Hz. When A and B are sounded together 5 beats per second are heard. When B and C are sounded together produces 4 beats per second. On loading A with wax 2 beats per second are produced with B. The frequency of B is

A
280 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
320 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
245 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
420 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 245 Hz
δA=250 Hz
Now, as A is waxed it's frequency is decreased.
As A's frequency is decreased, beat is decreased so A has greater frequency then frequency of B.
So, beat=δAδB
5=250δB
δB=245 Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Phase Difference and Resultant Amplitude
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon