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Phase Difference

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Question

There are three tuning forks A, B and C. Frequency of A is 250 Hz. When A and B are sounded together 5 beats per second are heard. When B and C are sounded together produces 4 beats per second. On loading A with wax 2 beats per second are produced with B. The frequency of B is

A

280 Hz

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B

320 Hz

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C

245 Hz

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D

420 Hz

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Solution

The correct option is A 245 Hz
$δ_{A} = 250 H_{z}$
Now, as A is waxed it's frequency is decreased.
As A's frequency is decreased, beat is decreased so A has greater frequency then frequency of B.
So, $b e a t = δ_{A} - δ_{B}$
$5 = 250 - δ_{B}$
$\Rightarrow δ_{B} = 245 H_{z}$

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