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Standard X

Mathematics

Random Experiment

There are twe...

Question

There are twenty cards. Ten of these cards have the letter "I" printed on them and the other 10 have the letter "T" printed on them. If three cards are picked up at random and kept in the same order, the probability of making word IIT is

4/27

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5/38

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1/8

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9/80

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Solution

The correct option is B 5/38
$P (f o r m i n g o f t h e w o r d " I I T ") = P (a p p e a r a n c e o f f i r s t I) \times P (a p p e a r a n c e o f s e c o n d I) \times P (a p p e a r a n c e o f f i r s t T) = \frac{10}{20} \times \frac{9}{19} \times \frac{10}{18} = \frac{5}{38}$

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There are twenty cards. Ten of these cards have the letter "I" printed on them and the other 10 have the letter "T" printed on them. If three cards are picked up at random and kept in the same order, the probability of making word IIT is

The correct option is B 5/38P(formingoftheword"IIT")=P(appearanceoffirstI)×P(appearanceofsecondI)×P(appearanceoffirstT)=1020×919×1018=538

The correct option is B 5/38
$P (f o r m i n g o f t h e w o r d " I I T ") = P (a p p e a r a n c e o f f i r s t I) \times P (a p p e a r a n c e o f s e c o n d I) \times P (a p p e a r a n c e o f f i r s t T) = \frac{10}{20} \times \frac{9}{19} \times \frac{10}{18} = \frac{5}{38}$