Question

There are two books of five volumes each and two books of two volumes each. In how many ways can these books be arranged in a shelf such that volumes of same books remain together?

• A. $38$
• B. $34$
• C. $56$
• D. $88$

Answer 1

Answer: (D)

$88$

$2$ books of $5$ volume each

$2$ books of $2$ volumes

Total there are $4$ sets of books

internal arrangements among

(a) $2$ books of $5$ volumes $=5!\times 5$

(b) $2$ books of $2$ volumes $=2\times 2!$

Arrangements of $4$ set $=4!$

Total ways

$\Rightarrow 4!\times 5!\times 5!\times 2!\times 2!$

$\Rightarrow 1382400$ Ways