There are two boxes. Each one contains paper slips marked $1$ to $10$ . If we take one slip from each box, what is the probability that both numbers are prime?

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Solution

If we draw one slip from each box, total number of possible pairs $= 10 \times 10 = 100$
Prime numbers between $1$ and $10$ are $2, 3, 5$ and $7$ .
Thus, there are $4$ prime numbers in each box.
$\Rightarrow$ Number of pairs such that two slips are prime $= 4 \times 4 = 16$
Thus, probability that both the slips are prime $= \frac{16}{100} = \frac{4}{25}$

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There are two boxes. Each one contains paper slips marked 1 to 10. If we take one slip from each box, what is the probability that both numbers are prime?

If we draw one slip from each box, total number of possible pairs=10×10=100Prime numbers between 1 and 10 are 2,3,5 and 7.Thus, there are 4 prime numbers in each box.⇒ Number of pairs such that two slips are prime =4×4=16Thus, probability that both the slips are prime =16100=425

There are two boxes. Each one contains paper slips marked $1$ to $10$ . If we take one slip from each box, what is the probability that both numbers are prime?