Question

There are two children in a family, then probability that both are girls is

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{3}{4}$
• D. $\frac{1}{3}$

Answer 1

The correct option is B $\frac{1}{4}$

Following cases are possible $\left(B_1{B}_2\right)\left(B_1{G}_2\right)\left(B_2{G}_1\right)\left(G_1{G}_2\right)$

total=$4$

both are girls $=1$.

$probability=\frac{1}{4}$.