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Standard VIII

Physics

Time

There are two...

Question

There are two clocks, both set to show $10 pm$ on $21^{st}$ January $2010.$ One clock gains $2$ minutes in an hour and the other clock loses $5$ minutes in an hour. Then by how many minutes do the two clocks differ at $4 pm$ on $22^{nd}$ January $2010$ ?

126

minutes

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136

minutes

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96

minutes

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106

minutes

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Solution

The correct option is A $126$ minutes
The two clocks show $10 pm$ on $21^{st}$ January $2010.$
One clock gains $2$ minutes in an hour.
Other clock loses $5$ minutes in an hour.
Time period between $10 pm$ and $4 pm = 18$ hours
$∴$ Difference $= 2 \times 18 + 5 \times 18$
$= 126$ minutes

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There are two clocks, both set to show 10 pm on 21st January 2010. One clock gains 2 minutes in an hour and the other clock loses 5 minutes in an hour. Then by how many minutes do the two clocks differ at 4 pm on 22nd January 2010?

The correct option is A 126 minutesThe two clocks show 10 pm on 21st January 2010. One clock gains 2 minutes in an hour. Other clock loses 5 minutes in an hour. Time period between 10 pm and 4 pm=18 hours ∴ Difference =2×18+5×18 =126 minutes

There are two clocks, both set to show $10 pm$ on $21^{st}$ January $2010.$ One clock gains $2$ minutes in an hour and the other clock loses $5$ minutes in an hour. Then by how many minutes do the two clocks differ at $4 pm$ on $22^{nd}$ January $2010$ ?

The correct option is A $126$ minutes
The two clocks show $10 pm$ on $21^{st}$ January $2010.$
One clock gains $2$ minutes in an hour.
Other clock loses $5$ minutes in an hour.
Time period between $10 pm$ and $4 pm = 18$ hours
$∴$ Difference $= 2 \times 18 + 5 \times 18$
$= 126$ minutes