Two clocks are set to show the correct time at 1:00am on a day. One clock loses 3 minutes in an hour and the other clock gains 3 minutes in an hour. Exactly after how many days will both the watches show the correct time? Assume that is a 12 hour clock.

Q. There are two clocks on a wall, both set right at 10:00 a.m. One clock is losing 2 minutes per hour and the other clock is gaining 3 minutes per hour. If the clock which is losing 2 minutes per hour shows 3:00 p.m. the next day, what time does the clock gaining 3 minutes per hour show?

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There are two clocks, both set to show 10 pm on 21st January 2010. One clock gains 2 minutes in an hour and the other clock loses 5 minutes in an hour. Then by how many minutes do the two clocks differ at 4 pm on 22nd January 2010?

The correct option is A 126 minutesThe two clocks show 10 pm on 21st January 2010. One clock gains 2 minutes in an hour. Other clock loses 5 minutes in an hour. Time period between 10 pm and 4 pm=18 hours ∴ Difference =2×18+5×18 =126 minutes

There are two clocks, both set to show $10 pm$ on $21^{st}$ January $2010.$ One clock gains $2$ minutes in an hour and the other clock loses $5$ minutes in an hour. Then by how many minutes do the two clocks differ at $4 pm$ on $22^{nd}$ January $2010$ ?

The correct option is A $126$ minutes
The two clocks show $10 pm$ on $21^{st}$ January $2010.$
One clock gains $2$ minutes in an hour.
Other clock loses $5$ minutes in an hour.
Time period between $10 pm$ and $4 pm = 18$ hours
$∴$ Difference $= 2 \times 18 + 5 \times 18$
$= 126$ minutes