Question

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Answer 1

Given : Length of cuboidal box l= 60 cm
Breadth of cuboidal box b = 40 cm
Height of cuboidal box h= 50 cm
Total surface area of cuboidal box = 2(lb+bh+hl)
$=2(60\times 40+40\times 50+50\times 60)=2(2400+2000+3000)=2\times 7400=14800c{m}^2$
(b) Given: Length of cuboidal box l = 50 cm
Breadth of cuboidal box b = 50 cm
Height of cuboidal box h = 50 cm
Total surface area of cuboidal box = 2(lb+bh+hl)
$=2(50\times 50+50\times 50+50\times 50)=2(2500+2500+2500)=2\times 7500=15000c{m}^2$
Hence, cuboidal box (a) requires the lesser amount of material to make, since surface area of box a is less than that of box (b).