The correct option is
A 40 W in series and 100 watt in parallel
Resistance,
R=V2/PWe assume rating voltage of both bulb is same, so
R∝1PThus,
40 W bulb has more resistance than the
100 W i.e
R40>R100When they are connected in series, same current flow through them.
Thus, heat produced,H=I2Rt or H∝R
So, 40 W bulb will more brighter than 100 W.
When they are connected in parallel, same potential across them.
Thus, heat produced, H=(V2/R)t or H∝1/R
So, 100 W bulb will more brighter than 40 W.