Question

There are two elements X and Y. 'X' is the element with the highest $IP$ value. 'Y' is the first element in a group possessing strongest reducing property. If X and Y lose 1 and 2 electrons respectively, calculate the $IP$ values of the resultant species.

• A. 57.2 and 122.4 eV
• B. 122.4 eV and 57.2ev
• C. 57.2ev and 27. 9 ev
• D. None of these

Answer 1

The correct option is A 57.2 and 122.4 eV

The element with the highest $IP$ value is helium. 'X' is helium. $IA$ group elements are the strongest reducing agents. First element of $IA$ group is lithium. 'X' loses one electron from the single electron species is equal to the energy of electron in that orbit calculated by Bohr's formula.
$H{e}^{+}\to IPvalue=E_n=-\frac{13.6}{1}\times 2^2$
$=57.2eV$
$L{i}^{+2}\to IPvalue=E_n=-\frac{13.6}{1}\times 3^2$
$=122.4eV$.