There are two examination rooms A and B. If 10students are sent from A to B, then the numbers of students in the rooms become equal. If 20 students are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is
letthenumberofstudentsinroomAbexandinroomBbey.(x−10)=y+10orx−y=20→(1)(x+20)=2(y−20)orx=2y−40−20x=2y−60or20+y=2y−60∴y=80thenx=y+20=100