Question

There are two Ferris wheels available in an amusement park. The fraction of seats occupied by each Ferris wheel is shown on number lines.
Find the number of times Wheel A is occupied than Wheel B?

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The correct option is A 2

Ferris Wheel A has $\frac{4}{6}$ seats filled.

Ferris Wheel B has $\frac{2}{6}$ seats filled.

By dividing $\frac{4}{6}$ by $\frac{2}{6}$, we can find how many times A is occupied more than B.

$\Rightarrow \frac{4}{6}$ $÷$ $\frac{6}{2}$ = $\frac{4}{6}$ $\times$$\frac{6}{2}$ = 2

Hence, Ferris Wheel A is occupied 2 times more than that of Ferris Wheel B.