There are two horns H1 and H2 on a car. When sounded together, the driver records 35 beats in 10 seconds. With horn H2 blowing and car moving towards a wall at a speed of 5 ms−1, the driver noticed a beat frequency of 5 Hz with the echo. When frequency of H1 is decreased, the beat frequency with two horns sounded together increases. Calculate the frequencies of the two horns H1 and H2 respectively.
[Speed of sound = 332 ms−1]
f′=f2(vv−vs)=f2(332332−5)
Now wall acts as a source of frequency f′. Frequency of echo received by the observer (in car) is
f′′=f′(332+5332)
⇒f′′=f2(332+5332−5)=f2(337327)
Given,
f′′−f2=5
∴f2[337327−1]=5
⇒f2=3272=163.5 Hz
From (1),
f1=163.5±3.5=167 Hz or 160 Hz
Given, when frequency of H1 decreases, it gives more beats with H2.
⇒f1<f2 initially
∴f1=f2−3.5=160 Hz