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Question

There are two horns H1 and H2 on a car. When sounded together, the driver records 35 beats in 10 seconds. With horn H2 blowing and car moving towards a wall at a speed of 5 ms1, the driver noticed a beat frequency of 5 Hz with the echo. When frequency of H1 is decreased, the beat frequency with two horns sounded together increases. Calculate the frequencies of the two horns H1 and H2 respectively.

[Speed of sound = 332 ms1]

A
167 Hz , 170.5 Hz
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B
167 Hz , 160 Hz
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C
160 Hz , 163.5 Hz
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D
170.5 Hz , 167 Hz
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Solution

The correct option is C 160 Hz , 163.5 Hz
Given,
f1=f2±3.5.......(1)
Velocity of sound, v=332 m/s
Velocity of source (car), vs=5 m/s



Consider wall as observer. Frequency received by the wall when only the second horn is sounded, is

f=f2(vvvs)=f2(3323325)

Now wall acts as a source of frequency f. Frequency of echo received by the observer (in car) is

f′′=f(332+5332)

f′′=f2(332+53325)=f2(337327)

Given,

f′′f2=5

f2[3373271]=5

f2=3272=163.5 Hz

From (1),

f1=163.5±3.5=167 Hz or 160 Hz

Given, when frequency of H1 decreases, it gives more beats with H2.
f1<f2 initially

f1=f23.5=160 Hz


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