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Standard XII

Physics

Simple Harmonic Oscillation

There are two...

Question

There are two identical springs each of spring constant $k$ . Here springs, pulley and rods are massless and block has mass $m$ . What is the extension of each spring at equilibrium?

\frac{2 m g}{k}

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\frac{m g}{2 k}

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\frac{3 m g}{4 k}

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\frac{m g}{k}

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Solution

The correct option is D $\frac{m g}{k}$
Draw a free body diagram of above figure
FBD of lower rod
$k x + k x = 2 m g$
$\Rightarrow x = \frac{m g}{k}$ .

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There are two identical springs each of spring constant k. Here springs, pulley and rods are massless and block has mass m. What is the extension of each spring at equilibrium?

The correct option is D mgkDraw a free body diagram of above figureFBD of lower rodkx+kx=2mg⇒x=mgk.

There are two identical springs each of spring constant $k$ . Here springs, pulley and rods are massless and block has mass $m$ . What is the extension of each spring at equilibrium?

The correct option is D $\frac{m g}{k}$
Draw a free body diagram of above figure
FBD of lower rod
$k x + k x = 2 m g$
$\Rightarrow x = \frac{m g}{k}$ .