There are two lines- AB and CD- which are parallel to each other- -AMN- 20- Find the value of x - 20-120-160-90-

The correct option is A 20^∘ ∠AMN = 20^∘ Also, AB || CD (given) So, ∠AMN = ∠MND (alternate interior angles). So, ∠MND = 20^∘ ...

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Standard VI

Mathematics

Interior Alternate Angles

There are two...

Question

There are two lines, AB and CD, which are parallel to each other. ∠AMN= $20^{\circ}$ . Find the value of x .

$160^{\circ}$

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$20^{\circ}$

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$120^{\circ}$

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90 $^{\circ}$

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Solution

The correct option is B
$20^{\circ}$

$∠$ AMN = $20^{\circ}$

Also, AB || CD (given)
So, $∠$ AMN = $∠$ MND (alternate interior angles).

So, $∠$ MND = $20^{\circ}$

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There are two lines, AB and CD, which are parallel to each other. ∠AMN= 20∘. Find the value of x .

The correct option is B 20∘ ∠AMN = 20∘ Also, AB || CD (given) So, ∠AMN = ∠MND (alternate interior angles). So, ∠MND = 20∘

There are two lines, AB and CD, which are parallel to each other. ∠AMN= $20^{\circ}$ . Find the value of x .

The correct option is B
$20^{\circ}$

$∠$ AMN = $20^{\circ}$

Also, AB || CD (given)
So, $∠$ AMN = $∠$ MND (alternate interior angles).

So, $∠$ MND = $20^{\circ}$