There are two mass less spring A and B of spring constant KA and KBrespectively and KA > KB If WA and WB be denoted as work done on A and work done on B respectively, then
if they are compressed to same distance, WA>WB
if they are compressed by same force (upto equilibrium state) WA<WB
WA=12KAx2; WB=12KBx2 ∵KA>KB⇒WA>WB
If the springs are compressed by same force.
F=KAxA=KBxB; xA=FKA; xB=FKBWAWB=12KAF2K2A12KBF2K2B=KBKAWA<WB