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Question

There are two mass less springs A and B of spring constant KA and KB respectively and KA>KB if WA and WB be denoted as work done on A and work done on B respectively, then:

A
If they are compressed by same distance WA=WB
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B
If they are compressed by same force(upto equilibrium state) WA=WB
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C
If they are compressed to same distance WA>WB
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D
If they are compressed by same force(upto equilibrium state) WA>WB
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Solution

The correct option is C If they are compressed to same distance WA>WB
According to question
KA>KB
WA=+12KAx2 [ Work is done by spring is =1Kx2]
WB=+12KBx2[ Here, work is done on spring. Hence force, and displacement is in same direction]
KA>KB
WA>WB
If FA=FB
KAxA=KBxBxA=(KBKA)xBxA<xB
WA=+12KAx2A=12(KAxA)xA=12FAxA
WB=+12KBx2B=12(KBxB)xB=12FBxB
WB>WA

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