Question

There are two mugs of capacities $600\text{mL and}300\text{mL}$, respectively. How many times would you use the following mugs to take out $6\text{L}$ of oil without spillage?
Number of mugs with a capacity of $600\text{mL}=\text{A}$
Number of mugs with a capacity of $300\text{mL}=\text{B}$

• A. $10\text{A mugs},20\text{B mugs}$
• B. $10\text{A mugs},10\text{B mugs}$
• C. $20\text{A mugs},10\text{B mugs}$
• D. $20\text{A mugs},20\text{B mugs}$

Answer 1

The correct option is A $10\text{A mugs},20\text{B mugs}$

$1\text{L}=1,000\text{mL, so}6\text{L}=6\times 1,000=6,000\text{mL}$
First mug:
Capacity of each mug $=600\text{mL}$
Number of times the mug is used $=6,000÷600=10$
So, $10\text{A mugs}$
Second mug:
Capacity of each mug $=300\text{mL}$
Number of times the mug is used $=6,000÷300=20$
So, $20\text{B mugs}$
Hence, option A is correct.