There are two mutually perpendicular forces acting on an object. One force acts in the direction of motion of the object and the direction of other force is perpendicular to the motion. During this interval, the kinetic energy of the body changes from 25 J to 100 J. The work done by the force acting perpendicular to the direction of the object is:

75 J

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0 J

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25 J

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100 J

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Solution

The correct option is B
0 J

Work done by force $F_{L}$

W = $F_{L} . S = | F_{L} | | S | c o s 90^{\circ}$

W = 0

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There are two mutually perpendicular forces acting on an object. One force acts in the direction of motion of the object and the direction of other force is perpendicular to the motion. During this interval the kinetic energy of the body changes from 25J to 100J. What is the work done by the force acting perpendicular to the direction of object?

Two mutually perpendicular forces are acting on a moving object. One force acts in the direction of motion of the object and the other force acts perpendicular to the direction of motion. During this interval, the kinetic energy of the body changes from 25 J to 100 J and the direction of motion is unaffected. The work done by the force acting perpendicular to the direction of the motion is:

A force acts in the direction of motion of the object. During this interval the kinetic energy of the body changes from $25 J$ to $100 J$ . The work done by the force is

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The correct option is B 0 J Work done by force FL W = FL.S=|FL||S|cos90∘ W = 0

The correct option is B
0 J

Work done by force $F_{L}$

W = $F_{L} . S = | F_{L} | | S | c o s 90^{\circ}$

W = 0