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Question

There are two mutually perpendicular forces acting on an object. One force acts in the direction of motion of the object and the direction of other force is perpendicular to the motion. During this interval, the kinetic energy of the body changes from 25 J to 100 J. The work done by the force acting perpendicular to the direction of the object is:


  1. 75 J

  2. 0 J

  3. 100 J

  4. 25 J


Solution

The correct option is B

0 J


Work done by force FL

W = FL.S=|FL||S|cos90

W = 0

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