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There are two...

Question

There are two sample of $H C l$ having molarity 1 M and 0.25 M. Find volume of these sample taken in order to prepare 0.75 M $H C l$ solution.
(Assume no water is used)

20 ml, 10 ml

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100 ml, 50 ml

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40 ml, 20 ml

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50 ml, 25 ml

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Solution

The correct options are
A 20 ml, 10 ml
B 100 ml, 50 ml
C 40 ml, 20 ml
D 50 ml, 25 ml
Final molarity $= \frac{V_{1} \times 1 + V_{2} \times 0.25}{(V_{1} + V_{2})}$
$0.75 (V_{1} + V_{2}) = V_{1} + 0.25 V_{2}$
$0.75 V_{1} + 0.75 V_{2} = V_{1} + 0.25 V_{2}$
$0.5 V_{2} = 0.25 V_{1}$
$\frac{V_{1}}{V_{2}} = 2$
So, ratio of $\frac{V_{1}}{V_{2}}$ should be 2

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(Assume no water is used)

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Types of Solution

Standard XII Chemistry

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There are two sample of HCl having molarity 1 M and 0.25 M. Find volume of these sample taken in order to prepare 0.75 M HCl solution. (Assume no water is used)

The correct options are A 20 ml, 10 ml B 100 ml, 50 ml C 40 ml, 20 ml D 50 ml, 25 mlFinal molarity =V1×1+V2×0.25(V1+V2) 0.75 (V1+V2)=V1+0.25V2 0.75 V1+0.75 V2=V1+0.25V2 0.5 V2=0.25 V1 V1V2=2 So, ratio of V1V2 should be 2

There are two sample of $H C l$ having molarity 1 M and 0.25 M. Find volume of these sample taken in order to prepare 0.75 M $H C l$ solution.
(Assume no water is used)